-9/(x-6)^2=0

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Solution for -9/(x-6)^2=0 equation: 


D( x )

(x-6)^2 = 0

(x-6)^2 = 0

(x-6)^2 = 0

x-6 = 0 // + 6

x = 6

x in (-oo:6) U (6:+oo)

-9/((x-6)^2) = 0

-9 = 0

x belongs to the empty set

x belongs to the empty set

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